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event_available2026-07-13
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Use Descartes' Rule of Signs to determine how many positive and how many negative real zeros the polynomial can have. Then determine the possible total number
of real zeros. (Enter your answers as comma-separated lists.)
P(x)-*-+-+-x+5
number of positive zeros possible
number of negative zeros possible
number of real zeros possible
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O-15 points SPreCaic7 3.4.090
Show that the polynomial does not have any rational zeros.
P(x) 50-625+ 4x²-1
We first determine all the possible rational zeros of P(x). (Enter your answers as a comma-separated list.)
x=
Starting with the smaller possible rational zero, we evaluate the polynomial.
smaller possible rational zero
larger possible rational zero
Therefore, there are no rational zeros.
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