The system x'(t) = (x-3) (y-1) y' (t) = (x-5) (y-3), has the equilibrium point (3, 3). The linearization at this point has the form z' (t) = Az(t), where A is a) 2 -3 -3 -2 b) -3 -3 -5 c) 2 0 -2 d) 3 "(39) 5