A solid shaft ABCDE is supported by bearings at A and D, and rotates at 800 RPM. A power P (kW) is delivered to the shaft through the dc diameter belt pulley at C. 40% of the power is extracted via the dB diameter pulley at B, while the rest is extracted at the dд diameter pulley at E. At pulleys B and E, the two belt strands are parallel and at pulley C the total contact angle of the belt is 200 degrees. The ratio of tensions in them is R. B Info Power(kW) 15 AB(mm) 150 BC(mm) 80 CD(mm) 120 DE(mm) 50 dC (mm) 300 dB (mm) 240 dE (mm) 180 R 8:1 B 45 C E D Torque at TC= 179.05 N*m TD=71.62 N*m TE=107.43 N*m 1. Need FBD for XZ plane 2. Shear diagram XZ plane 3. Moment diagram XZ plane Power input is at point C: 60 15000 Watts T₂ = 2 800 rpm T = 179.05 Nm Point B extracts 40% of power: TB T 0.40 = 179.05 N m 0.4 = * TB 71.62 N* m Point E extracts 60% if power: TE=TC 0.60 = 179.05 N m 0.6 * TE 107.43 N m