60 d 2 m F₂-300N B 3 m F,=700N 0 M-1500Nm For the above diagram, given that F, = 600 N, 6 = 60 degrees and d = 4.5 m, calculate the following (neglect the depth of the beam): The magnitude of the resultant of the applied forces, F. Please provide the answer in kilo Newtons and report to three significant figures. Please include the unit ("KN") within your answer (e.g. if the calculated answer was 55.562 Newtons please input: 55.6 KN). Answer: The angle between the resultant force, F, and the negative x axis (measured anti clockwise from the negative x axis). Please provide the answer in degrees and report to three significant figures. Please include the unit ("deg") within your answer (e.g. if the calculated answer was 55.562 degrees please input: 55.6 deg). Answer: Locate the resultant force, F, so that it is equivalent to the system of applied forces. Calculate the offset distance of the resultant force, F, measured from point A along beam ABC. Please provide the answer in metres and report to three significant figures. Please include the unit ("m") within your answer (e.g. if the calculated answer was 55.562 metres please input: 55.6 m). Answer: