The free energy change for the following reaction at 25 °C, when [Co²+] = 2.13×103 M and [Pb2+] = 1.17 M, is 45.4 kJ: Co²+(2.13×103 M) + Pb(s) Co(s) + Pb²* (1.17 M) AG = 45.4 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction? The free energy change for the following reaction at 25 °C, when [Co²+] = 7.27×103 M and [Pb2+] = 1.18 M, is 42.3 kJ: Co²+(7.27×103 M) + Pb(s) Co(s) + Pb²+ (1.18 M) AG = 42.3 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction? The free energy change for the following reaction at 25 °C, when [Ag"] = 1.13 M and [Ni] = 9.87×10°³ M, is -214 kJ: 2Ag* (1.13 M) + Ni(s)2Ag(s) + Ni²+(9.87×103 M) AG=-214 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction?