The solution of a certain differential equation is of the form y(t) = aet + bet, where a and b are constants. The solution has initial conditions y(0) = 5 and y'(0) = 5. Find the solution by using the initial conditions to get linear equations fo a and b. y(t)=3e^t+2e^(61) 募 Preview 3et + 2e6t syntax ok