) Example 14-6 Air enters a window air conditioner at 1 atm, 30°C, and 80 percent relative humidity at a rate of 10 m³/min and leaves as saturated air at 14 °C. Part of the moisture in the air that condenses during the process is also removed at 14 °C. Calculate the rate of heat and moisture removal from the air. Rate of heat removal? Rate of moisture removal? T2=147 Saturatal ar Cooling coils (00000000000000 Air++ یانه ی ها = ma 0=100% Ti=30°C 0,=80% Condensate mf T3=146 V=10m³/min 9tm