A 380-V, four-pole, 60-Hz, Y-connected wound- rotor induction motor is rated at 10 hp. Its equivalent circuit components are: R₁ = 0.22, R2 = 0.10 2, X=0.5, X₂ = 0.50 XMF, RC=00, Pec=250 Pcore=100W. W. For a slip of s=5%, find the (show units) a) Line current I₁ b) Input Pin c) Stator copper loss PSCL d) Air gap power PAG e) Rotor copper loss PRCL f) Converted power PCONV g) Output power Pout! h) Motor efficiency n P=2W. I₁ R₁ jx₁ jx₂ mm mm V₁ = V jx L