The system x' (t) = (x 2) (y - 2) - y' (t) = (x-3)(y-1), has the equilibrium point (2, 1). The linearization at this point has the form z'(t) = Az(t), where A is a) 0 " (69) 0 -1 b) ( -2 1 -3 c) 2 2 ° ° (² 3) 3 1 d) "G -2 1 -1