TC (liquid) 1300 L: 35 wt% Ni a: 46 wt% Ni 1200 24 L+a a 32 (solid) m L: 35 wt%Ni 43 L+a 46 Cu-Ni system L: 32 wt% Ni a: 43 wt% Ni L: 2 wt% Ni a: 35 wt% Ni a: 35 wt% Ni 8. In the case that the binary alloy contains two components that have limited solubility, we call this a binary eutectic system. For example, Cu-Ag and Sn-Pb alloys. Since two components in a binary alloy have limited solubility, only a small amount of A can be solubilized in B and vice versa. By happening so, two types of alloys are made: (1) a (small A in lots of B); and (2) ẞ (small B in lots of A). The middle of the phase diagram contains a + ẞ. The point where liquid transforms into solid (a + B) is called. which provides (1). and (2) 110 OL 20 355 30 35 40 50 Cu-Ag wt% Ni 9. In T(° C) system 1200 the binary L (liquid) eutectic phase diagram, we can get the three information and we can use lever rule to calculate the weight fraction of each phase. For a 40 wt% Sn-60 wt% Pb alloy at 150°C, determine: (a) Phases: (b) Phase composition:_ (c) Relative amount of each phase (weight fraction): 10. For a 40 wt% Sn-60 wt% Pb alloy at 220°C, determine: a) Phases: TE 400 1000- a L+a 800 779 C 8.0 71.9 91.3 600 a+ẞ 200 0 20 18 40 100 60 CE 80 C, wt% Ag b) Phase composition: c) Relative amount of each phase (weight fraction): Pb-Sn T(°C) system T(°C) Pb-Sn system 300 L (liquid) L+G 300+ L (liquid) 220-a 200- R S L+a 183°C a 200 183 C +B 18.3 61.9 97.8 100+ a+ẞ 150 100 a+ẞ 0 20 20 T 0 20 12 60 80 100 C, wt% Sn 40 430 60 80 100 Co C, wt% Sn 2