5. (20 points) For the circuit in the figure below (a) Solve for Vi (b) Find the average power, reactive power and the apparent power absorbed by the voltage source (use negative sign for delivered power). (c) Find the average power, reactive power and the apparent power absorbed by the load. Write the values in the boxes. The signs and units matter. j100 + load -100 -120 Q V₂ V₁ -j100 2V 50 1250 (a) 6 points (b) 3 points (c) 2 points (d) 2 points (e) 3 points (f) 2 points Solve for V₁= Average power delivered by the voltage source, P = Reactive power delivered by the voltage source, Q= Apparent power delivered by the voltage source, [S] = Average power absorbed by the load, P= Reactive power absorbed by the load, Q= (g) 2 points Apparent power absorbed by the load, [S] = 11 11