1=0 L-.64 H C-1 μF R The equation that identifies the response parameter, s, of the parallel circuit shown above is: 2 1 1 $1,2=-- 2RC 2RC) LC • To get started, let's just determine the two values of s for a resistance of 2002. Hint: 1 μF = 1e-6 F. • Next, create a vector composed of 20 values for R ranging from 100 to 1000 (using either the linspace command or the colon operator). Evaluate s. Refine your values of R until you find the size of resistor that yields a pure real value of s. What is the final value of R? What the problem is asking for you to do is to find the value of R that sets the term under the square- root sign to zero. To do this, you generate your vector of R values, and then you have a choice of two different techniques where you can pick the one that makes the most sense to you. (a) Calculate s and zoom in on the resistor values where the imaginary part of s changes from zero to non-zero (this also can be described as where s changes from complex to real) or (b) Evaluate the term under the square-root sign and zoom in on the resistor values where this term changes from positive to negative. • Continue to repeat the calculation, manually changing the range (low and high values) of R values to zoom in on the desired point. It is very important that you understand how to do this problem on "pen and paper" before you attempt to program it. You can easily solve for the value of R analytically, however the way MATLAB is going to solve it would be more like setting up two columns in Microsoft Excel, where the left column contains the R values and the right column(s) are the s values or the square root terms. Display the resistor and both s values (or resistor and square root term, depending on which technique you used) in a table, with the resistor value in the left column and the other in the right column(s). This table will have either two or three columns and should have twenty values, and the final value of R should be somewhere in the middle of the list.