(20% ) Problem 4: Unpolarized light of intensity Io-950 W/m² is incident upon three polarizers. The axis of the first polarizer is vertical. The axis of the second polarizer is rotated at an angle 0-35° from the vertical. The axis of the third polarizer is horizontal. Randomized Variables 10-950 W/m² 8-35° #000 Otheexpertta.com 20% Part (a) What is the intensity of the light in W/m-after it passes through the first polarizer? sin() cotan() cos() tan() Π ( 8 9 HOME asin() acos() 4 5 6 atan() acotan() sinh() . 1 2 3 cosh() tanh() cotanh() + 0 . END Grade Summary Deductions Potential Submissions 0% 100% Attempts remaining: 201 (0% per attempt) detailed view Degrees Radians NO BACKSPACE CLEAR Submit Hint Hints: 0% deduction per hint. Hints remaining: 1 Feedback I give up! Feedback: 0% deduction per feedback A 20% Part (b) What is the intensity of the light in W/m2 after it passes through the second polarizer? & 20% Part (c) What is the intensity in W/m² of the light after it passes through the third polarizer? A 20% Part (d) Write an equation for the intensity of light after it has passed through all three polarizers in terms of the intensity of unpolarized light entering the first polarizer Io and the angle of the second polarizer relative to the first, given that the first and third polarizers are crossed (90° between them). Use trigonometric identities to simplify and give the results in terms of a single trigonometric function of p-20 A 20% Part (e) What is the smallest angle 02, in degrees, from the vertical that the second polarizer could be rotated such that the intensity of light passing through all three polarizers is I,'- 16 W/m²? All conte © 2017 Expert TA LLC