a. ди at - 22 и მx2 = 0, 0 < x < 2, 0 < t; u(0,t) = u(2,t) = 0, 0 <t, u(x, 0) = sin 2лx, 0 ≤x≤2. = Use h = 0.4 and k = 0.1, and compare your results at t = 0.5 to the actual solution u(x,t) = e-4x² sin 2лx. Then use h = 0.4 and k = 0.05, and compare the answers. ди a²u b. = at მx2 0. 0<x<л, 0 < t; u(0,t) = u(x,t) = 0, == u(x, 0) = sinx, 0 <t, 0≤x≤л. Use h = л/10 and k u(x,t) = e sin .x. = 0.05, and compare your results at t = 0.5 to the actual solution