تم الحل ✓
categoryهندسة مدنية
schoolبكالوريوس
event_available2026-07-16
السؤال
Transcribed Image Text:
Minimum
transverse
reinforcement
= No. 4 (No. 13)
hoops and crossties
@ 4" spacing
Spandrel beams
27" x 36" (top flange
effective width - 54")
5 No. 10 (No. 32) top
5 No. 9 (No. 29) bottom
Hoops and
crossties
not shown
for clarity
Normal beam
27" x 36"
5 No. 9 (No. 29) top
5 No. 8 (No. 25) bottom
(a)
Column 36" x 36"
12 No. 11 (No. 36)
story height = 12'
(b)
(c)
Asfy 7.59 x 60 = 455 kips
60455
455
4.96
Mnb
33.4
=
1172 ft-kips
12
2
X 60 300 kips
A,fy = 5.00 x 60
5.00
300
1.63
Mnb
33.4
=
815 ft-kips
12
2
Pu
fcAg
2210
0.426
upper column
4 X 1296
Pu
2306
= 0.445
lower column
fA 4 × 1296
X
Mnc
0.167
R
=
fAgh
36
Mac 0.167 X 4 X 1296 X
2597 ft-kips
Mnc
R
=
fcAgh
0.164
36
пс
Mac 0.164 X 4 X 1296 X
2550 ft-kips
12
ΣΜ
2597 +25505147 ft-kips
EM 1172815 = 1987 ft-kips
M
ΣΜΑ ΣΕ ΣΜ
nb⋅
14-12.5
So
S = 4+
= 4.5 in.
3
Ash = 0.3
4 X 33 X 41296
60
1089
− 1) = 0.50 in²
4 X 33 X 4
Ash = 0.09
0.79 in²
60
T₁ + C₂
=T+TV
col
col
Joint depth = h
in plane of
reinforcement
generating shear
Effective
joint width
≤ b + h
b+2x
b+ 2x
Reinforcement
generating shear
Direction of forces
generating shear
19-1
x
Effective area
20 √√√ Aj
C
15√√√√ A
12VfAj
Idh
dh
fydb
65Vf
dm
1.6(l
P1 +
dm
1.6l 0.6l
M3
V3
M2
b
V2
T₂
C2
VAMA
(a)
C3 V3
T3
V4 C4
V₁
12M₁
Τι
b
C₁
T4
(b)
№3
-V3
2
M2<M₁M₁
V4
N4
Story height
1
2
3
Displacement
(a)
(b)
(c)
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