Example #2.10; page 39 A stone thrown from the top of a building is given an initial velocity of 20.0 m/s straight upward. The building is 50.0 m high, and the stone just misses the edge of the roof on its way down, as shown in Figure 2.14. Using A =0 as the time the stone leaves the thrower's hand at position, deter- mine (A) the time at which the stone reaches its maximum height, (B) the maximum height, (C) the time at which the stone returns to the height from which it was thrown, (D) the velocity of the stone at this instant, and (E) the veloc- ity and position of the stone at 5.00 s. =2.04 s -20.4 m 31-0 e--9.80 m/s² 31-0 A 20.0 m/s A--9.80 m/s² 4- 4.08 s X-8 =-20.0 m/ dc--9.80 m/s 50.0 m -5.00 s 3--22.5 m 0-29.0 m yo -9.80 m, Vp=