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categoryهندسة كهربائية schoolبكالوريوس event_available2026-07-13

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x[n] = 45[n] 35[n-1] + 25[n—2] + [n 3] - YKWXK x[n] = [n] + 25[n-2]+5[n 3 h[n] = S[n]+5[n-1]+25n-3 = x[n]g[n].........and.....y2[n] = x2[n]g[n] [u]th g[n] = . = [h[n], n = 0, 1, 2] 0, n = 3,4,5 x1[n] = Ja[n], n = 0, 1,2,3] 0, n = 4,5 x2[n] = {xn+4], n = 0, 1, 2, 3] 0, n = 4,5 Y1[n].andy2[n] Y2[n

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