Data Set # 2 Assigned metal = aluminum mass of metal = = initial temperature of metal = mass of water in calorimeter = initial temperature of water in calorimeter = 25.0g 150.0 °C 150.0 g 20.0 °C data set # 2 identity of metal = Aluminum mass of metal, mmetal = 25.08 initial temperature of metal, Ti,metal = 150.0 °C mass of water, mwater = 150.0 initial temperature of water, Ti,water = 20.0°C final temp. of water and metal, T₁ = ANALYSIS Calculations: A1. (Refer back to Figure 3 for help with these calculations) The following data and calculations refer to the water in the calorimeter. Calculate the requested quantities from your data and enter the results in the table. Show all equations and work with units. change in temperature of water in calorimeter = = 24.5-20.0 4.5°C heat energy absorbed by water in calorimeter = 1.00cal Heat = 150.08 (182) 4.5% 82).4.5%. Water Master= SHwer 150.09 1.00 AT 45°C Qesie=> 605 cal 615 cal A2. The following data and calculations refer to the metal Calculate the requested quantities from your data and enter the results in the table. Show all equations and work with units. change in temperature of the metal cylinder ATM TE-TI =24.5-150 = -125.5°C how much heat energy did the metal transfer.to.the water? (remember the Law of Conservation of Energy) 9 metal = -q water metal=-65 cal cat Mal SH ST= Qmatal calculate the specific heat of the metal in show equation and work). SH metal metal Mmetal (Tmetal) = -675501 25.08-(-125.5°C) sal Metal 25.04 ?0.215.cal/gc -125.5°C 605 cal = 0.215139 = 0,215 col/gc Calculate the specific heat of the metal in (1 cal = 4.184 J) (show work). Click on the box in the simulation that shows the value of the specific heat in these units and compare. Are your calculations correct? SH=0.215x 4.184J goc 0.89956 = 0.9003/9°c