1 -4-3 Let A = -3 3 0 b₁ and b= b₂ Show that the equation Ax = b does not have a solution for all possible b, and describe the set of all b for which Ax=b does have a solution. 4 2 6 b3 How can it be shown that the equation Ax = b does not have a solution for all possible b? Choose the correct answer below. OA. Row reduce the augmented matrix [ A b ] to demonstrate that [ A b ] has a pivot position in every row. OB. Find a vector b for which the solution to Ax = b is the zero vector. OC. Row reduce the matrix A to demonstrate that A has a pivot position in every row. D. Row reduce the matrix A to demonstrate that A does not have a pivot position in every row. OE. Find a vector x for which Ax = b is the zero vector. Describe the set of all b for which Ax = b does have a solution. 0= (Type an expression using b₁, b₂, and b3 as the variables and 1 as the coefficient of b 3.)