2) Two forces are applied to a block of mass M equal to 24 kg sitting on a horizontal, table as shown in the figure. Assume Y- positive direction toward the upper side of your paper sheet AND perpendicular to the table top. One force F2 has a magnitude of 20 N and is directed at an angle 82 equal to 53° (positive 53) from the x direction as labeled in the figure below. As a result of the forces, the block experiences an acceleration a equal to 0.9 m/s2 in the x-direction only. The coefficient of kinetic friction between the block and table is 0.2. K (a) Do a complete free body diagram on the figure, indicating and naming all forces. You can call F1 "F1" and F2 "F2", but al other forces must be given their proper names and directions. Don't worry about magnitudes (size of vector) (2 pt) 1 02 m = =24Kg F2 = 20N = 53° NK = 0.2 a= 0.9m/52x 1 Fix Fi F₁x F₂Y F₁₂ F₂Y (b) Find the x and y components of the second force F1. (3 pts) 7.0