n-Butane is converted to isobutane in a continuous isomerization reactor that operates isothermally at 129.0°C. The feed to the reactor contains 87.00 mole% n-butane, 11.00% isobutane, and 2.00% HCI at 129.0°C, and a 50.00% conversion of n-butane is achieved. In the following calculations, one should use at least five significant figures. Physical Property Tables Feed and Product Composition Taking a basis of 1 mol of feed gas, calculate the moles of each component of the feed and product mixtures and the extent of reaction, . Basis 1 mol total nin (mol) nout (mol) n-butane iso-butane HCI ६ Calculate the standard heat of the isomerization reaction (KJ). Then, taking the feed and product species at 25°C as references, calculate and fill in the component amounts (mol) and specific enthalpies (kJ/mol) in an inlet-outlet enthalpy table. (See Example 9.5-1.) n-butane isobutane HCI ΔΗ KJ In Out Λ m (mol) Λ Hi (kJ/mol) nj (mol) H;(kJ/mol) By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor. Calculate the amount of heat transfer (kJ) to or from the reactor (state which it is) for a basis of 1 mol of feed and the same conversion. For a reactor feed of 325 mol/h, determine the required heat transfer rate (kW) for the reactor. Q = Heat is transferred k] (for 1 mol of 1 feed) the reactor. Q (signed) = kW (for a feed rate of 325 mol/h) By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor. Heat of Reaction Use your calculated results to estimate the heat of the isomerization reaction at 129.0°C. AH₂(129.0°C) = the tolerance is +/-9% kJ Attempts: 0 of 1 used SUBMIT ANSWER % Earn Maximum Points available only if you answer this question correctly in your first attempt.