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categoryرياضيات
schoolبكالوريوس
event_available2026-07-15
السؤال
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Question 1 (1 point)
Find the general solution of the given first-order linear differential equation.
dy y
dt
-
18te
y=-18te + C
y=-18te + Ct
y = -91² e²² + Ct 2
y = -9t² et + Ct
Question 2 (1 point)
Solve the problem.
A highly anticipated offering of 275,000 shares of a growth stock is presented to the market, and
half the offered shares are purchased when the market opens at 6:30 A.M. Each hour during the
trading day, 75,000 previously uncirculated shares are purchased and 20% of the shares currently
in circulation are resold. Set up an initial value problem for the number of shares s(t) in
circulation t hours into the trading day.
dS
dt
-0.20S = 75,000; S(0) = 137,500
dS
dt
+0.20S 75,000; S(0) = 275,000
dS
0.20S = 75,000; S(0) = 275,000
dt
dt
+0.20S = 75,000; S(0) = 137,500
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