Question [Numerical analysis]: Solve f(x)=x5 f(x) = x5 3.5x + 2.75 x3 + 2.125 x2 -3.875 x + 1.25 (a) Graphically. (b) Using two different java Commands. [3] [3] (c) Using Bisection method. Select an appropriate initial interval. Justify your selection to the interval. [4] (d) Using False-position method with initial interval [1, 3]. (e) Using Newton's method with initial valuex0 = 1.5. (f) Which method you think is better to use? Justify your answer. [4] [4] [2]