As a torque activity, your Physics TA sets up the arrangement shown below. 112 A uniform rod of mass m, = 153 g and length L = 100.0 cm is attached to the wall with a pin as shown. Cords are attached to the rod at the r₁ = 10.0 cm and r2 = 90.0 cm mark, passed over pulleys, and masses of m₁ = 246 g and m2 = 167 g are attached. Your TA asks you to determine the following. (a) The position r3 on the rod where you would suspend a mass m3 = 200 g in order to balance the rod and keep it horizontal if released from a horizontal position. In addition, for this case, what force (magnitude and direction) does the pin exert on the rod? Use standard angle notation to determine the direction of the force the pin exerts on the rod. Express the direction of the force the pin exerts on the rod as the angle F, measured with respect to the positive x-axis (counterclockwise is positive and clockwise is negative). 13 = Fp = 6=-90 x m X N (b) Let's now remove the mass m3 and determine the new mass mд you would need to suspend from the rod at the position r4 = 20.0 cm in order to balance the rod and keep it horizontal if released from a horizontal position. In addition, for this case, what force (magnitude and direction) does the pin exert on the rod? Express the direction of the force the pin exerts on the rod as the angle #F, measured with respect to the positive x-axis (counterclockwise is positive and clockwise is negative). m4= Fp Өр = 90 x kg X N о (c) Let's now remove the mass mд and determine the mass mg you would suspend from the rod in order to have a situation such that the pin does not exert a force on the rod and the location r from which you would suspend this mass in order to balance the rod and keep it horizontal if released from a horizontal position. m5 = r5 = x kg x m