To determine the angular momentum, we first find the moment of inertia 1 = 1m² + m² (0.500)² = 12 1 12 (0.100) (1.00)²+(0.400)(0.500)³ = 0.1083kg. m² The angular momentum of the system when the meter stick is pivoted about an axis perpendicular to the table through the 50.0cm mark will be L = 10 = (0.1083kg m³) (4.00rad/s) m²/s = 0.433kg m2