(10%) Problem 10: A jogger with mass m = 55 kg uses energy at a rate of P = 558 W when she jogs on horizontal ground at a constant speed of s = 3.2 m/s. The efficiency of her "human engine" however, is e = 0.37. (In other words, the power used for locomotion is e = 0.37 times the total power.) A 50% Part (a) Write an expression for the rate of energy expenditure when she jogs at the same constant speed up a slope of o = 5.14 degrees. Assume whatever frictional or drag forces are the same in each case. Your answer should be in terms of the symbols given in the problem statement and g (9.80 m/s²). 50% Part (b) What is the rate of energy expenditure when she jogs up the slope, in watts? P = W ( ) 7 8 9 HOME ETL456 1 2 3 Grade Summary Deductions Potential Submissions 0% 100% Attempts remaining: 15 (0% per attempt) detailed view sin() cotan() cos() tan Π asin() acos() atan() acotan sinh() cosh() tanh() cotanh() Degrees Radians + 0 END DEL CLEAR NO BACKSPACE Submit Hint Feedback Hints: 0 for a 0% deduction. Hints remaining: 0 Submission History I give up! Feedback: 0% deduction per feedback. All Date times are displayed in Eastern Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback