Applying Kirchoff's rules to the resistive circuit shown here results in the set of equations given below. Solve for the currents. + dc(15) R1 1000 2000 www R2 20 R4 24000 3000 www R3 23 R₁₁+R₁₂ = 15 R₁IRI RI₁ = 0 - R₂12-R313 = 0 11-12-13=0 1. Set up the coefficient matrix. (Don't forget to include Os for missing terms) Store the matrix in a variable called M. 2. Set up the column vector for the right-hand side - call it V. 3. Use the left division operator to solve for the currents - store the solution in a variable called I. 1 R1 = 2 100; R2 = 200; R3 = 300; R4 = 400; 3 Complete the following lines 4 5 M = [ ] ; 6 V = []; 7 8 I = []; 9