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categoryرياضيات
schoolبكالوريوس
event_available2026-07-15
السؤال
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2.
-/2 points ✓
ZILLDIFFEQMODAP11 4.2.005.
The indicated function y₁ (X) is a solution of the given differential equation. Use reduction of order or formula (5) in Section 4.2,
e-SP(x) dx
Y2 = Y₁(x) / ·
dx
(5)
y(x)
as instructed, to find a second solution y2(x).
Y2
=
y" - y = 0; Y1
= cosh x
4.
-/2 points ▼
ZILLDIFFEQMODAP11 4.2.011.
The indicated function y₁(x) is a solution of the given differential equation. Use reduction of order or formula (5) in Section 4.2,
e-SP(x) dx
Y₂ = X1(x)
-dx
(5)
V₁₂√(x)
as instructed, to find a second solution y₂(x).
Y2
=
xy" + y' = 0;
=
Y1 In x
5.
-/2 points ✓
ZILLDIFFEQMODAP11 4.2.015.
The indicated function y₁ (X) is a solution of the given differential equation. Use reduction of order or formula (5) in Section 4.2,
Y2 = Yı(x)
e-SP(x) dx
[
-dx
(5)
y(x)
as instructed, to find a second solution y 2(x).
(1 - 2x - x²)y" + 2(1 + x)y' - 2y = 0; ₁ = x+1
Y2
=
6.
-/2 points ✓
ZILLDIFFEQMODAP11 4.2.016.
The indicated function y₁(x) is a solution of the given differential equation. Use reduction of order or formula (5) in Section 4.2,
-SP(x) dx
Y
1/2 = 1/2(x) /
dx
(5)
as instructed, to find a second solution y₂(x).
Y1
(1 - x²)y" + 2xy' = 0; y₁ = 1
Y2
=
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