Coefficient Design In Exercises 79-84, determine the value(s) of k such that the system of linear equations has the indicated number of solutions. 79. No solution x + ky = 2 kx + y = 4 81. Exactly one solution kx+2ky+3kz = 4k x+ y + z= 0 2x- y+ z= 1 83. Infinitely many solutions 4x+ky = 6 kx+y=-3 84. Infinitely many solutions kx + y = 16 3x-4y=-64 80. Exactly one solution x+ky = 0 kx + y = 0 82. No solution x+2y+ kz6 3x+6y+8z = 4 85. Determine the values of k such that the system of linear equations does not have a unique solution. x+y+kz = 3 Discovery In Exer represented by the Gaussian elimination the elimination proc What do you obserw 91. x 4y=-3 5x - 6y=13 Writing In Exerc two equations appe of equations algebr misleading. 93. 100y-x= 99y-x= -3-1 3- -3- x+ky + z = 2 kx + y + z = 1