2. Cylinder Stresses Consider two long cylinders of two different materials where one cylinder fits just inside the other cylinder. The inner radius of the inner cylinder is a = 0.192 in, and its outer radius is b = 0.25 in. The inner radius of the outer cylinder is also b, and its outer radius is c = 0.312 in as shown. When the system is subjected a radial compressive displacement a hoop stress develops at the interface of the two cylinders. This so called hoop stress for both cyliders at the interface wall is given by σ₁ = + B₁ and 0₂ = + B₂ where / represents the inner cylinder and 2 represents the outer cylinder. Constants A1, A2, B1, and B2 are determined by solving the differential equation that governs this problem. This resulting system of linear equations based on the solution of the mentioned differential differential equation is not given here, but below is the equation. a² 0 0 b² -1 -8² B₁ 0 -(1+) (1)² (1+2)EE -(1-2)²EJE A₂ 0 0 -(1 + 1/2) (1-v)² B₂ -U.Exc where v=v2 = 0.4 (Poisson's ratio), E₁ = 3 x 10' psi, E2-3.5 x 10 psi (Modulus of elasticity), and U. 0.01 in (radial compressive displacement). Write an m-file that will solve the above matrix for constants A1, A2, B1, and B2 and then within the same m-file using this result calculate the hoop stresses 1 and 2 that occur between the cylinder walls. Note that r= b= 0.25 in at the two cylinder wall interface. Intermediate answers: (do not report them in your solution) A 221.95 lb, A2 15.01 lb, B₁ =-6020.64 psi B2=-2229.40 psi << Report your answer in the following format: Hoop Stress-1... psi and Hoop Stress-2 = ... psi (See the notes on m-file output basics for this type of formatting). 01-9571.8 psi, 02 = -1989.3 psi