(1 point) 0. Let The flow system shown in the figure is activated at time t = Qi(t) denote the amount of solute present in the ith tank at time t. Assume that all the flow rates are a constant 10 L/min. It follows that the volume of solution in each tank remains constant; assume this volume to be 1000 L. The concentration of solute in the inflow to Tank 1 (from a source other than Tank 2) is 0.2 kg/L, and the concentration of solute in the inflow to Tank 2 (from a source other than Tank 1) is 0 kg/L. Assume each tank is mixed perfectly. a. Set up a system of first-order differential equations that models this situation. Qi -1/50 1/100 Q1 2 + Q₂ 1/100 -1/50 Q2 0 b. If Q1 (0) = 30 kg and Q2(0) = 0 kg, find the amount of solute in each tank after t minutes. Q1(t)=(55/3)e^(-3/100)t+(-85)e^(-1/100)t+(400/3) Q2(t)=(55/3)e^(-3/100)+(-85)e^(-1/100)+(200/3) c. Ast∞, how much solute is in each tank? In the long run, Tank 1 will have 400/3 In the long run, Tank 2 will have 200/3 kg of solute. kg of solute. (Reread the question and think about why this answer makes sense.) kg kg