2) A regenerative gas turbine power plant is shown in Figure 2. Air enters the compressor at 100 kPa, 300K with a mass flowrate of 5.8 kg/s. The turbine inlet temperature is 1400 K. The compressor pressure ratio is 8 and turbine and compressor operate isentropically. The power plant incorporates a regenerator with effectiveness of 80% and negligible pressure drop. Property data is given in Table 2. Sketch a labelled T vs s diagram for the cycle showing the state points and determine (by air-standard analysis) the following: a) the net power developed (in kW); b) the heat input to the Combustor (in kW); c) the cycle thermal efficiency; d) the rate of exergy destruction in the regenerator, in kW, for To 300 K. Table 2: Property Data for Cycle Regenerator Hmmmm y www 2in Neg 80% Combustor hx - h₂ State Point Pressure Temp. enthalpy Entropy Nocy = h₁-h₂ kPa K (kJ/kg) (kJ/kg-K) 3- 1 100 300 300.19 5.706 T₁ = 1400 K 23 2 800 540.1 544.8 5.706 3 800 1400 1515.4 6.768 4 100 834.6 Compressor 860.5 6.768 Turbine W cycle x 800 777.2 Find from reg 6.093 Y 100 600.5 Find from Ex bal 6.413 T₁ = 300 K P₁ = 100 kPa Figure 2 (20 Marks)