6) According to the following reaction, what mass of PbCl2 can form from 235 mL of 0.110 M KCl solution? Assume that there is excess Pb(NO3)2. A) 7.19 g B) 3.59 g C) 1.80 g D) 5.94 g E) 1.30 g 2 KCl(aq) + Pb(NO3)2(aq) → PbCl2(s) + 2 KNO3(aq) - JCL solution reacts