The one-line diagram of a simple power system is shown in Figure 1. The neutral of each generator is grounded through a current-limiting reactor of 0.25/3 per unit on a 100-MVA base. The system data expressed in per unit on a common 100-MVA base is tabulated below. The generators are running on no-load at their rated voltage and rated frequency with their emfs in phase. Determine the fault current for the following faults giving Zo=j0.35, Z₁ = j0.22 and Z₂ = j0.22. (a) A balanced three-phase fault at bus 3 through a fault impedance Z = 0.1j pu. (b) A single line-to-ground fault at bus 3 through a fault impedance Z = 0.1j pu. (c) A line-to-line fault at bus 3 through a fault impedance Z, = 0.1j pu. (d) A double line-to-ground fault at bus 3 through a fault impedance Z = 0.1j pu. G₁ T₁ T₂ Figure 1. G2 Table 1. Item BaseMVA Voltage Rating X¹ x² хо 55333 G₁ G₂ 100 T₁ T₂ L12 L13 L23 8888888 100 20kV 0.15 0.15 0.05 20kV 0.15 0.15 0.05 100 20/220 kV 0.10 0.10 0.10 100 20/220 kV 0.10 0.10 0.10 100 220kV 0.125 0.125 0.30 100 220kV 0.15 0.15 0.35 100 220kV 0.25 0.25 0.7125