Problem 1. (5 points) Answer by True/False. No justification required. (a) The following is a separable first-order ordinary differential equation, dy = t2y² +4. (b) There is only one solution y(t) to the initial value problem dy = 3t², y(0) = 2. dt (c) If F(t) is an antiderivative of f(t), then y = . F(t) is a solution to the differential equation dy = f(t). dt