3. Determine all linear and angular accelerations by graphical acceleration analysis for the given position = 60° of the mechanism. Draw to scale the acceleration vector diagram encompassing all linear accelerations to scale, and present the results in tabular form. or the six-bar linkage mechanism s 1₁ =OE= 0.92m 12=0A = 0.23m 1₁ = AB=070m 1₁ = BE=0.60m 4 1, CD= 0.92m AC = 0.42m H=00375m B= 10° 6₁ = 30° m₂ = 530 Rpm w₂ = 8, Determine all possible position echanism shown below, determine: 2 w₂ = 8₂ 0, 8₂ =60° C S H ང་ D '6 ossible positions of links and joints by graphical position analysi 6.20 W2 530rpm = 530 * 2 * /60 = 55.5rad/s VOA = 0.23 * 55.5 = 12.77m/s From the figure: AB = 13.5m/s⇒ WAB = 13.5/0.7 = 19.29rad/s VEB = 2.51m/s ⇒ WEB = 2.51/0.6 = 4.18rad/s VCD = 3.25m/s ⇒ WCD = 3.25/0.92 = 3.533rad/s VAC = 8.10m/s up=6.2m/s (slider) Comment> e 50 FM = Chegg Study Textbook Solutions asdads answered this 1.055 answers Was this answer helpful? A D 8.10 C 12.77 6.20 w2=530rpm = 530*2* π/60 = 55.5rad/s VOA = 0.23 * 55.5= 12.77m/s From the figure: VAB 13.5m/swAB = 13.5/0.7 = 19.29rad/s ① 13.50 E.O 51 B