Find the power delivered to the element in Example 1.5 at t = 5 ms if the current remains the same but the voltage is: (a) v = 2i V, (b) v = (10+5 f'idt) V. Answer: (a) 17.27 W, (b) 29.7 W. Find the power delivered to an element at 1 = 3 ms if the current entering its positive terminal is i=5 cos 60лt A =UT and the voltage is: (a) v=3i, (b) u = 3 di/dt. Solution: (a) The voltage is v=3i = 15 cos 60л1; hence, the power is At t = 3 ms, p = vi = 75 cos² 60лt W p=75 cos² (60x x 3 x 10-3)=75 cos2 0.18 = 53.48 W (b) We find the voltage and the power as 1.5 di v=3- 3(-60л)5 sin 60лt=-900л sin 60л V di p=vi=-4500л sin 60лt cos 60лt W Att = 3 ms, p=-4500л sin 0.18л cos 0.18л W =-14137.167 sin 32.4° cos 32.4° = -6.396 kW == Find the power delivered to the element in Example 1.5 at t = 5 ms if the current remains the same but the voltage is: (a) v = 2i V, (b) v = V. (10+5 idi) v. Answer: (a) 17.27 W, (b) 29.7 W. ==